Question

calculate the energy and frequency of the radiation emitted when an electron jumps from n=2 to n=1 in hydrogen atom​

Answer 1

Answer:

Explanation:

Wavelength is represented by λ and is given by following expression

λ

1

​  

=R[  

n  

1

2

​  

 

1

​  

−  

n  

2

2

​  

 

1

​  

]

λ

1

​  

=(109677cm  

−1

)[  

2  

2

 

1

​  

−  

3  

2

 

1

​  

]

⇒  

λ

1

​  

=1523291.67m  

−1

 

Frequency ν is given by  

ν=  

λ

c

​  

=4.57×10  

14

s  

−1