Question

calculate the energy and frequency of the radiation emitted when an electron jumps from n=2 to n=1 in hydrogen atom​

Answer 1

Answer:

Wavelength is represented by λ and is given by following expression

λ

1

=R[

n

1

2

1

−

n

2

2

1

]

λ

1

=(109677cm

−1

)[

2

2

1

−

3

2

1

]

⇒

λ

1

=1523291.67m

−1

Frequency ν is given by

ν=

λ

c

=4.57×10

14

s

−1

Explanation:

hope it helps you.......