Question

Calculate the energy associated with first orbit of he+

Answer 1

E = -13.6Z²/n² eV

For first orbit if He+ Z = 2 and n = 1
E = -13.6 × 2^2 / 1^2
E = -54.4 eV

Energy associated with first orbit of He+ atom is -54.4 eV

Answer 2

Answer:

The energy associated with first orbit of He+ is -54.380 eV

Explanation:

For the first orbit of helium atom, n = 1 and Z= 2 (Atomic number or proton number for helium atom)

According to the energy associated formula $\mathrm{E}_{\mathrm{n}}=(-13.595 \mathrm{eV}) \mathrm{Z}^{2} / \mathrm{n}^{2} \text { atom }^{-1}$

Now put the value of Z and n in the above formula.

$\mathrm{E}_{\mathrm{n}}=-13.595 \mathrm{eV} \mathrm{X} 4 / 1^{2}$

En = - 54.380 eV (Energy is expressed with negative sign because it take that amount of energy to unionize the electron from the helium nucleus.)