Question

Calculate the energy associated with photon of light having a wavelength 6000 A.(lamda . = 6.624 x 10-27 erg-sec)​

Answer 1

E = hc/L

where, E is the energy

h is the Plancks constant

c is the speed of light

L is the wavelength

E =

$\frac{6.626 \times {10}^{ - 31} \times 3 \times {10}^{8} }{6000 \times {10}^{ - 10} } = 3.313 \times {10}^{ - 16} joules$

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Answer 2

E = hc/L

where, E is the energy

h is the Plancks constant

c is the speed of light

L is the wavelength

E =

\frac{6.626 \times {10}^{ - 31} \times 3 \times {10}^{8} }{6000 \times {10}^{ - 10} } = 3.313 \times {10}^{ - 16} joules

6000×10

−10

6.626×10

−31

×3×10

8

=3.313×10

−16

joules