calculate the energy associated with photon of light having a wavelength of 6000 Amstrong.[h=6.624*10^-27 erg-sec.]
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as according to plank theory E=hf
so where f=c/wavelength so E=hc/wavelength
6.626×10^-34×3×10^6/6×10^-7
19.878×10^-28/6×10^-7
3.300×10^-21 m is ans
so where f=c/wavelength so E=hc/wavelength
6.626×10^-34×3×10^6/6×10^-7
19.878×10^-28/6×10^-7
3.300×10^-21 m is ans
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