Calculate the energy associated with the 2nd orbit of helium ?What is the radius of this orbit?
Pls give the answer with a proper steps
NCOs I have exam on Sunday
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Answers
Answered by
3
Explanation:
E = R × ( Z^2 / n^2)
( R = rydberg constant= -2.18 × 10^18
Z= atomic number....
n = number of shells....)
so, E = -2.18 ×10^18 ( 2^2 /2^2)
E = -2.18 × 10^18 Joules......
Answered by
0
Answer:
Z= 2
n = 2
To find energy associated to 2nd orbit of He+ :-
E = -2.18 ×10^-18( Z^2/n^2)J/atom
E = -2.18 × 10^-18
To find radius :-
Rn = 0.529 × (n^2/Z)
Rn = 1.058 A°
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