Question

calculate the energy associated with the first orbit of he+. what is the radius of this orbit​

Answer 1

Answer:

Explanation:

(a) calculate the energy associated with the first orbit of He  

+

 

E=−13.6  

n  

2

 

z  

2

 

​  

 

=−13.6×  

1  

2

 

2  

2

 

​  

=54.4 ev

Radius of orbit r=529×  

z

n  

2

 

​  

 nm

=529×  

2

12

​  

 

=264.5 nm

(b) lower value of n=5

s p d f g

Answer By

Answer 2

Explanation:

$\sf E_n = - \dfrac{(2.18×10^{-18}J)Z^2}{n^2}atom^{-1}$

For He+, n=1, Z=2

$\sf E_1=\dfrac{-(2.18×10^{-18}J)(2^2)}{1^2}$

$\sf =-8.72×10^{-18}J$

Radius of orbit,

$\sf r_n = \dfrac{(0.0529\:nm) {n^2} }{Z}$

• n=1
• Z=2

$\sf r_n = \dfrac{(0.0529\:nm) {1^2} }{2}$

$\sf = 0.02645 \: nm$