Question

calculate the
energy
associated
with the first orbit of He+,
What is the radius of this orbit

Answer 1

Answer:

calculate the energy associated with the first orbit of He

+

E=−13.6

n

2

z

2

=−13.6×

1

2

2

2

=54.4 ev

Radius of orbit r=529×

z

n

2

nm

=529×

2

12

=264.5 nm

(b) lower value of n=5

s p d f g

Answer 2

Explanation:

We know that,

$\underline{\boxed{\sf E_n=-2.18×10^{-18}×\dfrac{Z^2}{n^2}J}}$

• $\sf n=1$
• $\sf Z=2$

$\sf E_1=-2.18×10^{-18}×2^2 \: J$

$\sf E_1=-2.18×10^{-18}×4 \: J$

$\sf E_1= \bf -8.72×10^{-18}\: J$

We know that,

$\underline{\boxed{\sf r_n=0.0529×\dfrac{n^2}{Z}\: nm}}$

• $\sf n=1$
• $\sf Z=2$

$\sf r_n = \dfrac{0.0529}{2} \: nm$

$\sf r_n = \bf 0.02645 \: nm$