Question

Calculate the energy associated with the first orbit of li+2 ion

Answer 1

Answer:

E = (-13.595 * Z2)/n2 eV

Here, Z = 3 (atomic number of Li), n =1 (first orbit)

Put values in given formula, we get

E = (-13.595 * 32)/12 eV = -122.355 eV

Hence, the energy associated with the first orbit of Li2+ ion is -122.355 eV.

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Answer 2

Answer:

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Explanation: