Calculate the energy associated with the radiation with wavelength 3000 Å (in erg per quantum).
Answers
Answered by
3
Answer:
Correct Answer is
6.63×10 ^19 J
Given wavelength =3000A ^∘
E=hν
c=hν
v= c/λ
E=hc/λ
=6.626 x 1
0
−34
×
3000 × 10
−9
3 × 10
8
=6.626 x
10
−9
10
8
=6.626 x 1
0
−34
X 10
8
X 10
7
=6.626 x 1
0
−34
X 10
15
E= 6.626 x 1
0
−34
X 10
19
Joules.
Answered by
0
Answer:
Given wavelength =3000A
∘
E=hν
c=hν
v=
λ
c
E=h.
λ
c
=6.626 x 1
0
−34
×
3000 × 10
−9
3 × 10
8
=6.626 x
10
−9
10
8
=6.626 x 1
0
−34
X 10
8
X 10
7
=6.626 x 1
0
−34
X 10
15
E= 6.626 x 1
0
−34
X 10
19
Joules.
Explanation:
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