Question

Calculate the energy associated with the second orbit of li2+ ion.What is its radius

Answer 1

Dear Students,

◆ Answer -

E = -30.6 eV

R = 0.7053 A°

◆ Explanation -

Energy associated with 2nd Bohr's orbit is -

E = -13.6 Z²/n²

E = -13.6 × 3² / 2²

E = -30.6 eV

Radius of 2nd Bohr's orbit in Li2+ is given by -

R = 0.529 n²/Z

R = 0.529 × 2² / 3

R = 0.7053 A°

Hope this helps you...

Answer 2

Explanation:

r=0.529*n^2/z

z=3 for LI

n=3

r=0.529*9/3

r=1.587