Calculate the energy associated with the third orbit of hydrogen atom.
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As r = n2h2/4∏2 mke2,,
r = 9 × (6.6 × 10-34)2 × 9 × 109/ [4 × (22/7) × (22/7) × 9.1 × 10-31 (1.6 × 10-19)2,,
= 4.775 × 10-10 m,,
= 4.775 Å,,
E = - 2∏2 mk2 e4/n2h2,,
On putting the standard values, we get
E = - 2.43 × 10-19 J
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