Question

Calculate the energy consumed in 20 days, if two bulbs of 30w work for 6 hrs, three fans of 80 w work for 10 hrs daily and one tube of 60 w works for 3 hrs daily

Answer 1

Given conditions ⇒

For the Bulbs,
 Power of the bulbs = 30 W.
  = 0.03 kW.
 Time = 6 hours.
Energy consumed by 1 bulb in 1 day = 0.03 × 6
0.18 kWh.
∴ Energy consumed by two bulbs in 1 day = 2 × 0.18 = 0.36 kWh.

For Fans,
 Power = 80 W.
 = 0.08 kWh
Time = 10 hours.
Energy consumed by 1 fan in 1 day = 0.08 × 10 = 0.8 kWh.
∴ Energy consumed by 3 Fan in 1 day = 0.8 × 3 = 2.4 kWh.


For Tube lights,
Power = 60 W
 = 0.06 kWh.
Time = 3 hours.
Energy consumed by the 1 Tube lights in 1 day = 0.06 × 3 =  0.18 kWh.

Now, the total energy consumed by the Electric appliances in one day = 0.36 + 2.4 + 0.18
= 2.94 kWh.

∴ Total Energy consumed in  20 days = 20 × 2.94
 = 58.8 kWh.


Hope it helps.

Answer 2

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