Physics, asked by akarshgupta816, 5 hours ago

Calculate the energy difference between the ground state and first excited state for electron if the length of the box is 10^-8 ​

Answers

Answered by vikrambrainly
0

Answer:

The length of the box is 10^-8 \Delta E_n=\left(2^2-1\right) * h^2 / 8 m L^2

Explanation:

Step 1: As the centre barrier thickness rises, the energy gap between the ground and first excited state energy level narrows. The magnitude of the dipole matrix element also declines with the thickness of the central barrier, as shown in Figure.

Step 2: The ground state is the condition with the least energy. The excited state is the result of the electrons absorbing energy and launching themselves into the outer circles.

We prepare a ground condition first, then we calculate its energy. The energy of the first excited state is then measured after the first excited state has been prepared. In the previous scheme, the energy gap between them can be calculated by subtracting the first number from the second value.

Energy in one dimensional box is determined by

E_n=n^2 * h^2 / 8 m L^2

\Delta E_n=\left(2^2-1\right) * h^2 / 8 m L^2

h is planck's constant

L is length of the box.

m is mass of electron

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