Calculate the energy dissipated in kWh and J for a bulb of 250W. Which is used for 6 h
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Given :-
Power of the bulb = 250 W
Time required = 6 hours
To Find :-
The energy dissipated in kWh.
The energy dissipated in J.
Solution :-
We know that,
- e = Energy
- p = Power
- t = Time
Using the formula,
Given that,
Power (p) = 250 W
Time (t) = 6 hours = 21600 sec
Substituting their values,
⇒ 250 = E/21600
⇒ E = P × T
⇒ E = 250 × 21600
⇒ E = 5400000 J = 5.4 × 10⁶ J
Therefore, the energy dissipated is 5.4 × 10⁶ J.
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