Calculate the energy in joule, equivalent to the mass of one proton. The mass of proton
is 1.00728u. Express the energy in kilowatt-hour also.
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At resonance condition we observe maximum current flowing in a LCR circuit.
Thus, from graph both circuits have resonance frequency omega as 1
we have at resonanceω2=1LCfor ω=1we have,L=1C ( ans i)(ii) Power Factor=RZAs resistance of circuit 2 is greater than that of 1 ( can be observed from value of current )Thus, power factor of 2 is greater than that of R(iii) Quality factorQ=1RLC−−√ ( for series circuit )since L and C is same for both case.we see circuit (ii) has lesser value of max current correspondingly its resistancemust be greater.Thus Q∝1R we have Q factor of 1 greater than 2.
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