Question

calculate the energy in joules for lamda 6000 amstrong​

Answer 1

3000 is the joules for lamda 6000 Armstrong

Answer 2

Answer:

We know that, E=hv=h⋅λc

h=6.624×10−27erg−sec; c=3×1010cm/sec;

λ=6000A˚=6000×10−8cm

So, E=6×10−5(6.624×10−27)×(3×1010)=3.312×10−12erg.