Question

Calculate the energy in kj/mol when one mole of electrons in a sample of hydrogen atoms transitions from n = 6 to n = 3.

Answer 1

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Answer 2

Answer:

The energy released when when one mole of electrons in a sample of hydrogen atoms transitions from n = 6 to n = 3 is -110.098 kJ.

Explanation:

$E_n=-13.6\times \frac{Z^2}{n^2}ev$

where,

$E_n$ = energy of $n^{th}$ orbit

n = number of orbit

Z = atomic number

For hydrogen , Z = 1

$E_6=-13.6\times \frac{1^2}{6^2}eV=-0.37 eV$

$E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51 eV$

Change in energy n=6 to n=3 level.

$E_3-E_6=-1.51eV-(-0.37 eV)=-1.41 eV=-1.8283\times 10^{-22} kJ$

$1 eV=1.60218\times 10^{-22} kJ$

Energy released by single hydrogen atom on transition =$-1.8283\times 10^{-22} kJ$

1  mole = $6.022\times 10^{23} atoms$

Energy released by $6.022\times 10^{23}$ atoms hydrogen atom on transition:

=$-1.8283\times 10^{-22} kJ\times 6.022\times 10^{23} mol^{-1}=-110.098 kJ/mol$

The energy released when when one mole of electrons in a sample of hydrogen atoms transitions from n = 6 to n = 3 is -110.098 kJ.