Question

Calculate the energy loss in a perfectly inelastic collision if the mass of the object is 40 kg with velocity 4 m/s hits the object of mass 60 kg with velocity 2 m/s.​

Answer 1

Explanation:

Mass of first body m

1

=40 kg and its velocity u

1

=4 m/s

Mass of second body m

2

=60 kg and its velocity u

2

=2 m/s

Energy lost in perfectly inelastic collision ΔKE=

2

1

m

1

+m

2

m

1

m

2

(u

1

−u

2

)

2

∴ ΔKE=

2

1

(40+60)

(40)(60)

(4−2)

2

=48 J

Answer 2

Given:

Mass of first object  $m_1$ = 40 kg

velocity of first object $u_1$ = 4 m/s

Mass of second object  $m_2$ =60 kg

velocity of second object $u_2$ = 2 m/s

To find :

The energy loss in a perfectly inelastic collision.

Formula to be used:

ΔKE = $\frac{1}{2} (\frac{m_1m_2}{m_1+m_2} )(u_1 - u_2)^{2}$

Solution:

To find the energy lost in perfectly inelastic collision,

Substitute the values in the following formula,

ΔKE = $\frac{1}{2} (\frac{m_1m_2}{m_1+m_2} )(u_1 - u_2)^{2}$

ΔKE = $\frac{1}{2} (\frac{(40)(60)}{40+60} )(4 -2)^{2}$

ΔKE = $\frac{1}{2} (\frac{2400}{100} )(2)^{2}$

ΔKE = $\frac{1}{2} (24 )(4)$

ΔKE = 24 × 2

ΔKE = 48 J

Final answer:

The energy loss in a perfectly inelastic collision if the mass of the object is 40 kg with velocity 4 m/s hits the object of mass 60 kg with velocity 2 m/s is 48 J.