Question

calculate the energy of 1 mole of nitrogen gas at 27°c​

Answer 1

Explanation:

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Answer 2

The energy of 1 mole of nitrogen gas = 6235.5 J

According to the kinetic theory of gases , the kinetic of a diatomic gas like nitrogen at a particular temperature T is equal to 5/2 nRT.

A diatomic gas has 5 degree of freedoms - 2 rotational and 3 translational .

Kinetic Energy = 5/2 nRT

n = number of moles of the gas = 1

R = Universal gas constant = 8.314 J. mol-1. K-1

T = temperature of the gas = 27°C = 300K

kinetic Energy = 5/2 × 1 × 8.314 × 300

=> 6235.5 J