Calculate the energy of 1 mole of nitrogen gas at 27°C
Answers
Answered by
1
Answer:
The energy of one mole of nitrogen gas at 300 K (27°C) is equal to 6233.80 J.
Energy of one molecule of a diatomic gas at temperature(T) = 5×k×T/2.
Both nitrogen and hydrogen are diatomic gases.
One mole of any gas will contain NA(Avogadro's number) molecules of that gas.
Explanation:
Similar questions