Question

Calculate the energy of 1 mole of nitrogen gas at 27°C

Answer 1

Answer:

The energy of one mole of nitrogen gas at 300 K (27°C) is equal to 6233.80 J.

Energy of one molecule of a diatomic gas at temperature(T) = 5×k×T/2.

Both nitrogen and hydrogen are diatomic gases.

One mole of any gas will contain NA(Avogadro's number) molecules of that gas.

Explanation: