Question

Calculate the energy of 1 mole of nitrogen gas at 27oc. Compare the energy of 1 mole of hydrogen gas at this temperature with the corresponding value of nitrogen gas (Given : Boltzmann Constant (k=1.38 x 10-23 jk-1)

Answer 1

Answer:

Internal energy of 1 mole of hydrogen gas and nitrogen gas will be same and equal to 6232.5 J

Explanation:

As we know that internal energy of an ideal gas is given by the formula

$U = \frac{f}{2}nRT$

here we know that

f = degree of freedom of gas

for all diatomic gas we have 5 degrees of freedom

So we will have

$U = \frac{5}{2}(1)(8.31)(300)$

$U = 6232.5 J$

Now we know that hydrogen as well as Nitrogen both are diatomic gas and both are given at same temperature so both will have same energy.

#Learn

Topic : Internal energy of gas

https://brainly.in/question/2851794

Answer 2

The ideal gas law can be written in terms of the number of molecules of gas: PV = NkT, where P is pressure, V is volume, T is temperature, N is number of molecules, and k is the Boltzmann constant k = 1.38 × 10–23 J/K. A mole is the number of atoms in a 12-g sample of carbon-12.