Calculate the energy of a photon and the energy per mole of photons of radiation of wavelength 150pm
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Answer:
E=
λ
hc
=
150×10
−12
6.626×10
−34
×3×10
8
=1.325×10
−15
J.
The energy of the ejected electron is
2
1
mv
2
=
2
1
×9.11×10
−31
×(1.5×10
7
)
2
=1.025×10
−16
.
The energy with which the electron was bound to the nucleus is:
Energy of photon − Energy ejected by electron =13.25×10
−16
−1.025×10
−16
=12.225×10
−16
J
=7.63×10
3
eV.
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