Question

calculate the energy of a photon of light having a frequency of 2×10^8 s^-1​

Answer 1

Explanation:

E=hf

value of "h" planks constant is constant which is 6.625×10^-34Js ..

=(6.625×10^-34)(2×10^2)

E=13.25×10^-32 J

Answer

hope it will help