Question

Calculate the energy of a photon of light having frequency of 3*10to the power 15 sec inverse

Answer 1

frequency = $\large\rm { 3 × 10^{5} \ Hz}$

$\large\rm { E = hv}$

$\large\rm { = 6.626 × 10^{-34} J/s-1 × 3 × 10^{5} = 19.878 × 10^{-29} J }$

We know $\large\rm { c = \lambda v }$

v =$\large\rm { 3 × 10^{8} / 0.5 × 10^{-10} = 6×10^{18}}$

E = hv

E = $\large\boxed{\rm {3.97 × 10^{-15} J}}$

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