Question

Calculate the energy of a radiation having a wavelength of 4000A°

Answer 1

Answer:

3.1eV

PLZ:

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SHORTCUT:

E=1240eVnm/λ(nm)

Explanation:

λ=4000 * 10⁻¹⁰*10⁹=400 nm

E=1240eVnm/400 nm=1240/400eV=3.1eV