Question

calculate the energy of an electron in electron volt in the second orbit of Li+2ion​

Answer 1

Answer:

Energy = -13.6Z²/n²

= -13.6 * 4/4

= -13.6 eV

Radius = 0.529 n²/Z Å

= 0.529 * 4/2

= 1.058 Å

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