Question

Calculate the energy of an electron present in 2nd orbit of Li +3 ion

Answer 1

Answer:

Explanation:

The potential energy of an electron in the n  

th

 orbit is given by:

P.E.=−  

n  

2

 

27.2 z  

2

 

​  

 eV

As it is lithium-ion ‘z’=3 and as it is 2nd orbit, n=2.

Putting z=3,n=2,

P.E.=−  

2  

2

 

27.2×3  

2

 

​  

 

P.E=−61.2 eV

Hence, option A is correct.

Answer 2

Answer:

in second orbit only one