Calculate the energy of an electron which has de-Broglie wavelength 1 A.
Given h= 6.6 x 10-34 Js.
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frequency=speed/lambda
f=3×10^8/1
f=3×10^8
formula:e=h×f
e=6.6×10^-34×3×10^8
e=19.8×10^-26J
f=3×10^8/1
f=3×10^8
formula:e=h×f
e=6.6×10^-34×3×10^8
e=19.8×10^-26J
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