Question

Calculate the energy of an electron with wavelength 4250 A.

Answer 1

I am telling you a short trick

for energy of electron in eV,

E = 12400/lembda ( in A°)

here it is 2.91 eV by 12400/4250

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b..bye

Answer 2

Answer:

4.67*10^-19J

Explanation:

E=hc/lamda

=6.626*10^-34Js*3*10^8 ms^-1

/4250*10^-10m

=4.67*10^-19 J

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