Question

Calculate the energy of first, second and third shell of hydrogen atom.Also ,calculate the energy difference between first and second and third.​

Answer 1

Answer:

Explanation:

For this, we will use formula $E_{n} = \frac{-313.6}{n^{2}} \frac{kJ}{mole}$.

so, $E_{1}$ = -313.6 kJ/mole

$E_{2}$ = -313.6/4 kJ/mole = -78.4 kJ/mole

$E_{3}$ = -313.6/9 kJ/mole = -34.8444... kJ/mole = approx. -34.84 kJ/mole

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