Question

Calculate the energy of one mole of photons of radiation whose frequency is 7 ×10^12

Answer 1

E= nhf here f is 7×10^12, h is constant(6.67×10^-34) and n = no. of photon , in one mole no. of photon=avagadro no.(6.67×10^23) , .E =6.67×10^23×7×10^12×6.67×10^-34 , E=311.4×10^4 joule

Answer 2

Answer:

The energy of one photon = (E)=hv

Here, h=6.626×10^34 js

v=7×10^12

E=6.626×10^-34 ×7×10^12

= 46.382×10^-21 j

Thus, the energy of one mole of photons is E×A

where A is Avogadro number

46.382×10^-21 j× 6.022× 10^-23 mol

= 279.312× 10^-1 jmol

or

=279.312404×10^-1 jmol