Question

calculate the energy of photon having wavelength 4000 angstrom in electron volt and in jull

Answer 1

Answer:

4.9*10^-9 J

3.1059*10^10eV

Explanation:

Answer 2

The energy of photon having wavelength 4000A° in eV and joule are 3.10593 eV and  4.9695  × 10⁻¹⁹ Joule respectively.

We have to calculate the energy of photon having wavelength 4000A° in electron volt and in joule.

Using Plank's quantum theory,

The energy of photon is given by, E = hc/λ

where

• h is Plank's constant
• c is the speed of light in vacuum
• λ is the wavelength.

h = 6.626 × 10⁻³⁴ Js

c = 3 × 10⁸ m/s

λ = 4000A° = 4 × 10⁻⁷ m

∴ E = (6.626 × 10⁻³⁴ × 3 × 10⁸)/(4 × 10⁻⁷) Joule

= 4.9695 × 10⁻¹⁹ Joule

Therefore the energy of the photon in Joule is 4.9695 × 10⁻¹⁹ Joule.

Now energy in eV :

We know, 1 eV = 1.6 × 10⁻¹⁹ joule

∴ 4.9695 × 10⁻¹⁹ Joule = (4.9695 × 10⁻¹⁹)/(1.6 × 10⁻¹⁹) = 3.1059 eV

Therefore the energy of the photon in eV is 3.10593 eV.

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