Question

calculate the energy of photon having wavelength 600 angstrom​

Answer 1

Answer:

lambda=6000A

Frequency(f)=velocity(c)/lamba

F=speed of light/lambda

F=3×10^8/6000×10^-10

=0.5×10^15hz

F=5×10^14hz

Energy=hf

h=Planck constant

=6.63×10^-34×5×10^-14

E=3.315×10^-47J

Explanation:

Answer 2

${\huge{\underline{\large{\mathbb{ \green{VERIFIED \: ANSWER}}}}}}$

lamda=6000A

Frequency(f)=velocity(c)/lamda

F=speed of light/lamba

F=3×10^8/6000×10^-10

=0.5×10^15hz

F=5×10^14hz

Energy=hf

h=Planck constant

=6.63×10^-34×5×10^-14

E=3.315×10^-47J