CBSE BOARD X, asked by gaa222da, 1 year ago

Calculate the energy of photon of radiation whose 'v' is 5×10^14 Hz

Answers

Answered by Anonymous
1

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Answered by generalRd
3
Given,

Frequency,V= 5×10^14 Hz = 5×10^14s^-1

Plank's constant,h= 6.636 x 10-34 J s-1

Now, we know energy of one photon is given by=>

E = h×v

=>E =

6.636 x 10^-34 Js-1 × 5×10^14 s^-1

=>E = 33.18 × 10^-20 joules.

Now,we also know that-->

One mole of photon has

=> 6.023× 10^23 no. of photons

And,

Energy of one mole of photon is given by->

No. of photons× energy of one photon

=> (6.023 x 10^23 x 33.18 x 10^-20 J)

=> 199.51x 10^3 J

or

=> 199.51 kJ.

Hence the energy of photon of radiation whose 'v' is 5×10^14 Hz will be 119.84 kJ..
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