Question

Calculate the energy of the photon having the wavelength of 589 nm in Joules.

Given: h = 6.626 x 10-34​

Answer 1

Here we are have ti find energy:
h=planck's constant

Answer 2

To find:

Energy of a photon having the wavelength of 589 nm in Joules [Given : value of planck's Constant is 6.626 × 10^(-34)]

Calculation:

The general expression for energy possessed by an Electromagnetic wave is given as follows:

$\boxed{ \bold{E = \dfrac{hc}{ \lambda} }}$

Putting available values in SI units:

$\bold{ = > E = \dfrac{(6.626 \times {10}^{ - 34}) \times (3 \times {10}^{8}) }{589 \times {10}^{ - 9} } }$

$\bold{ = > E = \dfrac{(6.626 \times {10}^{ - 34}) \times (3 \times {10}^{(8 + 9)}) }{589 } }$

$\bold{ = > E = \dfrac{(6.626 \times {10}^{ - 34}) \times (3 \times {10}^{17}) }{589 } }$

$\bold{ = > E = \dfrac{6.626 \times {10}^{ (- 34 + 17)} \times 3 }{589 } }$

$\bold{ = > E = \dfrac{6.626 \times {10}^{ - 17} \times 3 }{589 } }$

$\bold{ = > E = 0.0337 \times {10}^{ - 17} \: joule}$

So, final answer is:

$\boxed{ \red{ \bold{ E = 0.0337 \times {10}^{ - 17} \: joule}}}$