Question

calculate the energy per quantum of light associated with the 700nm​

Answer 1

Answer:

$2.837$ × $10^{19} J$

Explanation:

Wavelength (w) = 700 nm = 700 × $10^{-9}$ m

Planck's constant (h) = 6.62 × $10^{-34}$ J s

Energy = $\frac{hc}{w}$ = (6.62×$10^{-34}$)(3×$10^{8}$)÷(700 × $10^{-9}$)

                   = $2.837$ × $10^{19} J$