Question

Calculate the energy released by the fission of 2g of U235 in kWh. Guven that the energy released per fission is 200MeV

Answer 1

Answer:

4.6 × 10⁴ kW-h

Explanation:

Given:

Mass of the U₂₃₅ = 2 g

Energy released per fission = 200 MeV

Molar mass of U₂₃₅ = 235 g/mol

now,

Number of moles of U₂₃₅ in 2 g = $\frac{2}{235}$ = 0.008595 moles

Now,

number of atoms in 0.008595 moles = number of moles × Avogadro's Number

thus,

number of atoms in 0.008595 moles = 0.008595 × 6.022 × 10²³ atoms

also,

200 MeV = 200 MeV × 1.602 × 10⁻¹⁹ J = 320.4 × 10⁻¹³ J

Therefore,

The energy released by 0.8595 moles

= 0.008595 × 6.022 × 10²³ × 320.4 × 10⁻¹³ J

or

= 16.58 × 10¹⁰ J

Now,

For J to kW-h

16.58 × 10¹⁰ J  in kW-h = $\frac{16.58\times10^{10}}{3600\times10^3}$

or

The energy released = 4.6 × 10⁴ kW-h