Calculate the energy released in the
nuclear reaction Li + p → 2a given
mass of Li atom and of helium atom to
be 7.016 u and 4.0026 u respectively.
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Answer:
12th
Physics
Nuclei
Nuclear Force and Binding Energy
Find the binding energy per...
PHYSICS
Find the binding energy per nucleon for lithium nucleus
3
Li
7
.
Take mass of
3
Li
7
=7u, mass of proton =1.007825u and mass of neutron =1.008665u.
Take 1u=931.5MeV.
December 26, 2019
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Edu Shejale
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ANSWER
Binding energy per nucleon. E=
A
△E
=
A
△m∗931
△m=(3M
p
+4M
n
)− Mass of
3
Li
7
Where,
M
p
is the mass of the proton
M
n
is the mass of the neutron
△m= (3 X 1.007825+4 X 1.008898)−7=0.059067
△E=0.059067 X 931=54.991377
E=
A
△E
=
7
54.991377
=7.736MeV
Explanation:
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