Question

calculate the energy released when 10 gm of water at 100°c is split on the hand . the specific heat capacity of water is taken to be 4200 j kg^-1 K^-1 and the temperature of the skin is 30°C.​

Answer 1

hope u understand ............

Answer 2

The energy released by the water to hand is 2940 J.

Explanation:

Given the mass of the water, m = 10 g = 0.010 g.

The specific heat capacity of water is $c_p=4200J/kg.K$.

The initial temperature of the water,$T_1=100 ^0C =100+273=373K$.

The final temperature of the water,$T_2=30 ^0C =100+30=303K$.

The change in temperature, $\Delta T=(373-303)=70K$.

The formula for heat released is given as

$Q=mc_p \Delta T$

substitute the given values, we get

$Q=0.010kg\times4200J/kg.K\times(373-303)$

$Q=0.010kg\times4200J/kg.K\times70$

$Q=2940J$.

Thus, the energy released by the water to hand is 2940 J.

#Learn More : heat released.

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