Physics, asked by puspaduwal, 2 months ago

Calculate the energy released when a uranium-238 nucleus splits into its natural components. Given that mass of proton = 1.007825 amu; mass of neutron = 1.008665 amu and mass of U238 = 238.0508 amu.

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Answered by Dikshaagree
2

Answer:

Binding Energy and Mass defect. Solutions. ...

a) Mass of component parts m = 2p+2n. = 2(1.672623 x 10-27) + 2(1.674929 x 10-27) ...

Mass defect. = 6.6950 x 10-27kg - 6.6447x 10-27kg. ...

b) Binding energy using E =mc2. = [5.03 x 10-29kg] x [3 x 108]2. ...

c) Binding energy. = 4.53 x 10-12 x 1.60 x 10-19. ...

[= 28.3 MeV ] a) 238

Explanation:

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Answered by honey77777777
0

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