Calculate the energy required to convert 85kg of ice to water
Answers
Answer:
Temperature is required to calculate energy for your question
Explanation:
Please mark an temperature
Answer:
It would require 28,390 kJ of energy to convert 85 kg of ice to water.
Explanation:
What is Latent heat of fusion?
Latent heat of fusion is the amount of heat energy required to change the phase of a substance from a solid to a liquid at its melting point, without changing its temperature.
In other words, it is the amount of energy required to break the intermolecular bonds between the molecules of a solid substance to transform it into a liquid.
The latent heat of fusion is typically expressed in units of joules per kilogram (J/kg) or calories per gram (cal/g). For example, the latent heat of fusion of water is approximately 334 J/kg or 80 cal/g.
The energy required to convert a substance from one phase to another is given by the formula:
Q = m * L
where Q is the energy required, m is the mass of the substance, and L is the heat of transformation (also known as the specific latent heat) for the substance.
For the conversion of ice to water, we need to consider two phases: solid ice at 0°C and liquid water at 0°C. The heat of transformation for this conversion is known as the specific latent heat of fusion, which is 334 kJ/kg.
Therefore, the amount of energy needed to melt 85 kg of ice into water is:
Q = m * L
Q = 85 kg * 334 kJ/kg
Q = 28,390 kJ
To know more about melting point , Visit:
https://brainly.in/question/572447
#SPJ3