Calculate the energy required to heat up 1kg of water by 30 degrees. (The specific heat capacity of water is 4200) E = mcθ
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Explanation:
q=heat , m= mass , c=specific heat
q = 1*4200*30
= 126000
In the given question , assuming the pressure and volume to be constant, Energy will be equal to the heat supplied to the system
therefore Q = E = 126000 = 126 KJ
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