Question

Calculate the energy required to heat up 1kg of water by 30 degrees. (The specific heat capacity of water is 4200) E = mcθ

Answer 1

Answer:

Explanation:

q=heat , m= mass , c=specific heat

$q = mc(T2-T1)$

q = 1*4200*30

 = 126000

In the given question , assuming the pressure and volume to be constant, Energy will be equal to the heat supplied to the system

therefore Q = E = 126000 = 126 KJ