calculate the energy required to melt 2 kg of ice. Given specific latent heat of fusion of ice is 336 * 10^3 J/kg
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Answer:
Total heat = Heat required to convert 2kg of ice to 2kg of water at 0℃ +Heat required to convert 2kg of water at 0℃ to 2kg of water at 20℃
Heat=mhfg+mCp\Delta t$$
Here, m(mass of ice)=2kg
hfg(latent heat of fusion of ice)=334kJ
Cp of water(specific heat)=4.187 kJ/kg-k
Δt(temperature difference) =20℃
Therefore,
Heat required=2×334+2×4.187×(20−0)
=835.48 kJ
Therefore, to melt 2kg of ice 835.48kJ of heat is required.
Explanation:
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