Question

Calculate the energy stored in a 5μF capacitor , if a DC voltage of 100V is applied across it

Answer 1

Answer:

2.5 × 10⁻² J

Explanation:

We have given :

Potential difference V = 100 V

Capacitor of 5 μ F

We are asked to find energy stored :

We know :

U = 1 / 2 C V²

Putting values here we get :

U = 1 / 2 × 5 × 10⁻⁶ × 100² J

= > U = 2.5 × 10⁻² J

Hence we get required answer!