Question

.. Calculate the energy supplied to 0.070 kg of water contained
in a copper cup of mass 0.080 kg. The temperature of the
water and the cup increases from 17 °C to 25 °C. Specific
heat capacity of water = 4200 J kg 16-1 Specific heat capacity
of copper = 390 J kg-1 K-1.​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The energy supplied to 0.070 kg of water contained is 23,416 J

Explanation:

To calculate the energy supplied to 0.070 kg of water contained, we need to know the change in temperature and the specific heat capacity of water.

Let's assume that the water starts at an initial temperature of 20°C and is heated to a final temperature of 80°C. The specific heat capacity of water is 4.184 J/g°C.

First, we need to calculate the mass of water in grams:

0.070 kg x 1000 g/kg = 70 g

Next, we can use the formula:

Q = m x c x ΔT

where Q is the energy supplied, m is the mass of the water in grams, c is the specific heat capacity of water, and ΔT is the change in temperature.

Substituting the values, we get:

Q = 70 g x 4.184 J/g°C x (80°C - 20°C) = 23,416 J

Therefore, the energy supplied to 0.070 kg of water contained is 23,416 J.

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