Question

calculate the energy transferred by 5 A current flowing through a resistor of 2 ohm for 30 min

Answer 1

Explanation:

Power = Current ×Current×Resistance = 5×5×2=50 W. Time taken=30 min=30×60 seconds =1800 s. So the energy transferred by 5 A current flowing through a resistor of 2 ohm for 30 min =50×1800 =Power × time taken=90000 J. Hope it helps you.