Question

Calculate the energy transferred by 5 A current flowing through a resistor of 2 for 30 minutes

Answer 1

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Energy=power*time.

E=P*t.

Energy in joules.

Power in watts.

Time in seconds.

Power=(current)*(current)*resistor.

P=(I)^2*R.

P=(5*5)*2.

P=50 Watts.

Time=t=30mins=30*60seconds=1800secs.

Energy=E=P*t.

E=50*1800.

E=90000 joules.

E=90kilo joules.

E=90k joules.

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Answer 2

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➧ P = 1² × R

➙ Cᴜʀʀᴇɴᴛ => 5 ᴀᴍᴘᴇʀᴇꜱ

➙ Rᴇꜱɪꜱᴛᴀɴᴄᴇ => 2 ᴏʜᴍꜱ

➙ Pᴏᴡᴇʀ => (5)² × 2

➾ 25 × 2

➾ 30 ᴡᴀᴛᴛꜱ

➾ 50 / 1000 ᴋW

➾ 0.05 ᴋᴡ

➧ Tɪᴍᴇ=> 30 ᴍɪɴ

➾ 30 / 60

➾ ½ ʜʀꜱ

➾ 0.5 ʜʀꜱ

➧ Eɴᴇʀɢʏ = P × ᴛ

➾ 0.05 × 0.5

➾0.025 Kᴡʜ...✔

Hope It Will Help.❤