calculate the energy transferred by a 5 ampere current flowing through a resistor for 30 minutes
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Answer:
- Given:
- I = 5 A
- R = 2
- T = 30 minutes / 1800 sec
- To Find:
- E=?
Solution :
- P = I²R
- P = 5²2
- P = 50 w ........(1)
- E = P×T
- E = 50×1800
- E=90000 J
or
- E= 90KJ
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