Question

Calculate the energy transferred by KWH by a 5 ampere. Current flowing through through a resistance of 2 ohm for 40minutes

Answer 1

Answer:

(1) Power = I^2 ×R

= 5^2×2

= 50 Watts

(2) Energy transferred = Power × Time

E = 50 × 40/60 Watt-hour

= (50×40)/(60×1000)

= 0.033 KWH